Kynea Numbers In C++

Kynea numbers are a special class of numbers in mathematics, defined as numbers of the form:

Kn=(2n+1)2−2

where n is a non-negative integer. These numbers have unique properties and are part of the study of number theory.

Understanding Kynea Numbers

To understand Kynea numbers better, let’s break down their mathematical expression:

  • Base Expression: Start with 2n, which involves exponentiation.
  • Increment: Add 1 to 2n, yielding 2n +1.
  • Square the Result: Square the sum to produce (2n+1)2
  • Subtract 2: Finally, subtract 2 to compute the Kynea number.

For example:

  • For n = 0: K0 = (2 0 + 1) 2 −2 = (1 + 1) 2 −2 = 4 − 2 = 2.
  • For n = 1: K1 = (2 1 + 1) 2 −2 = (2 + 1) 2 −2 = 9 − 2 = 7.
  • For n = 2: K2 = (2 2 + 1) 2 −2 = (4 + 1) 2 −2 = 25 − 2 = 23.
  • Key Characteristics of Kynea Numbers:

  • Growth: Kynea numbers snowball with increasing n due to the squaring operation•
  • Oddness: All Kynea numbers are odd because the term (2n+1)2 is always odd, and subtracting 2 from a bizarre number retains oddness•
  • Applications: Kynea numbers are of interest in primality testing, sequence generation, and cryptographic studies•
  • Example:

Let us take an example to illustrate the Kynea Number in C++ .

Example

#include <iostream>
#include <cmath> // For pow function
#include <vector>

using namespace std;

// Function to compute Kynea number for a given n
long long computeKyneaNumber(int n) {
    long long base = pow(2, n) + 1; // Calculate 2^n + 1
    return (base * base) - 2;       // Square it and subtract 2
}

// Function to generate a list of Kynea numbers up to a given limit
vector<long long> generateKyneaNumbers(int limit) {
    vector<long long> kyneaNumbers;
    for (int i = 0; i <= limit; ++i) {
        kyneaNumbers.push_back(computeKyneaNumber(i));
    }
    return kyneaNumbers;
}

int main() {
    int limit = 5; // Directly set the limit for n

    // Generate and display Kynea numbers
    vector<long long> kyneaNumbers = generateKyneaNumbers(limit);
    cout << "Kynea numbers up to n = " << limit << " are:" << endl;
    for (int i = 0; i < kyneaNumbers.size(); ++i) {
        cout << "K_" << i << " = " << kyneaNumbers[i] << endl;
    }

    return 0;
}

Output:

Output

Kynea numbers up to n = 5 are:
K_0 = 2
K_1 = 7
K_2 = 23
K_3 = 79
K_4 = 287
K_5 = 1087

Algorithm:

Understand the Formula. The Kynea number formula is:

Kn=(2 n +1) 2 −2

This formula calculates a Kynea number for a given.

2 n : Raise 2 to the power of

+1: Add 1 to the result of 2 n

2(Square): Square the value from the previous step•

-2: Subtract 2 to get the final Kynea number•

Fix the Range of Computation: Instead of waiting for user input, we directly decide how many Kynea numbers to calculate• For example, if the range is from n 0 to n = 5, the program will compute the first 6 Kynea numbers.

Compute Kynea Numbers for Each n

For every n in the range:

  • Raise 2 to the power n : Start by calculating 2 n . This snowballs as n increases.
  • Add 1 : Add 1 to the result of 2 n, giving 2 n + 1.
  • Square the Value : Multiply (2 n + 1) by itself to get (2 n + 1)
  • Subtract 2 : Finally, subtract 2 to calculate K n = (2 n + 1) 2 - 2.

Store Results: Save the computed Kynea numbers in a collection (like a list or vector )• This helps keep track of all the numbers and makes them easier to display later•

Display the Results: For each Kynea number, print its position n and the corresponding value Kn. This shows the relationship between n and the rapidly growing Kynea numbers.

Complexity Analysis:

Time Complexity:

The time complexity of computing Kynea numbers is O(n) for generating n numbers. For each number, calculating 2n using the pow functions is O(log n). Since this is repeated n times, the overall complexity becomes O(n. log n).

Space Complexity:

The space complexity of the Kynea number algorithm is O(n) due to the storage of the Kynea numbers in a vector• Each number is stored in memory, so as the number of computations grows, the space required increases linearly with the size of the input limit n•

Input Required

This code uses input(). Please provide values below: