We have the capability to transform any decimal numeral (base-10 (0 through 9)) into a binary numeral (base-2 (0 or 1)) using a C++ program.
Decimal Number
A decimal number is referred to as a base 10 number due to its range from 0 to 9, encompassing a total of 10 digits within this span. Any sequence of these digits represents a decimal number, for instance, 223, 585, 192, 0, 7, and so forth.
Binary Number
A binary number is classified as a base 2 numeral due to its exclusive use of 0s and 1s. Any sequence comprising solely of 0s and 1s represents a binary number, for instance, 1001, 101, 11111, 101010, and so forth.
Let's examine some binary representations for decimal numbers.
| Decimal | Binary |
|---|---|
1 |
0 |
2 |
10 |
3 |
11 |
4 |
100 |
5 |
101 |
6 |
110 |
7 |
111 |
8 |
1000 |
9 |
1001 |
10 |
1010 |
Decimal to Binary Conversion Algorithm
Divide the given number by 2 using the modulus operator and save the resulting remainder in an array.
Divide the numerical value by 2 using the / (division operator).
Repeat the second step iteratively until the numerical value exceeds zero.
Let's examine the C++ demonstration for converting a decimal number to binary.
Example
#include <iostream>
using namespace std;
int main()
{
int a[10], n, i;
cout<<"Enter the number to convert: ";
cin>>n;
for(i=0; n>0; i++)
{
a[i]=n%2;
n= n/2;
}
cout<<"Binary of the given number= ";
for(i=i-1 ;i>=0 ;i--)
{
cout<<a[i];
}
}
Output:
Enter the number to convert: 9
Binary of the given number= 1001
