Overloading In C++ Mcq Exercise 3

1. What is the best way to declare a friend function to overload the binary + operator in C ++?
Example
Copy
class A {

    int value;

public:

    A(int v) : value(v) {}

    friend A operator+(const A&, const A&);

};
Try it Yourself

• ✅ A operator+(A, A);
• ✅ A operator+(const A&, const A&);
• ✅ A operator+(A&);
• ✅ A operator+(const A&);

Explanation:

The correct answer is option (b). The friend function to overload the binary + operator should be declared with two parameters, both passed by constant reference.

1. Which keyword is used to overload an operator as a non-member function but still access private members?

• ✅ static
• ✅ friend
• ✅ virtual
• ✅ inline

Explanation:

The correct answer is option (a). The friend keyword permits a non-member function to access private members of a class for operator overloading.

1. Can the new and delete operators be overloaded in C++?

• ✅ Both
• ✅ None of the above

Explanation:

The correct answer is option (a). In C++, the new and delete operators can be overloaded to access memory allocation and deallocation.

1. Which of the following syntax overloads the unary minus (-) operator for a class?
Example
Copy
class A {

public:

    A operator-() const;

};
Try it Yourself

• ✅ A operator-(int);
• ✅ A operator-;
• ✅ A operator- const;
• ✅ A operator- &;

Explanation:

The correct answer is option (c). The unary minus operator - is overloaded as a const member function with no parameters.

1. What is the return type of the overloaded subscript operator in a class for read-only access?
Example
Copy
class A {

public:

    const int& operator[](size_t index) const;

};
Try it Yourself

• ✅ int&
• ✅ const int&
• ✅ int*

Explanation:

The correct answer is option (c). Since the subscript operator has read-only access, it must return a constant reference for the element type.

1. Which of the following statements about function call operator overloading is correct?

• ✅ It cannot be overloaded.
• ✅ It must be a friend function.
• ✅ It allows objects to be used as functions.
• ✅ It can only be overloaded in derived classes.

Explanation:

The correct answer is option (c). The function call operator can be overloaded to allow objects to be used because they are also functions.