C++ Math fdim

The function calculates the positive difference between two numbers.

Conditions :

Consider two numbers 'x' and 'y' :

If(x>y) : It returns (x-y); If(y>x) : It returns zero.

Syntax

float fdim(float x, float y);
double fdim(double x, double y);
long double fdim(long double x, long double y);
promoted fdim(Arithmetic x, Arithmetic y);

Note: If any argument has an integral type, then it is cast to double. If any other argument is long double, then it is cast to long double.

Parameter

(x,y) : The values whose difference is to be calculated.

Return value

It returns the positive difference between x and y.

Example 1

Let's see a simple example when the value of 'x' is greater than the value of 'y'.

#include <iostream>
#include<math.h>
using namespace std;
int main()
{
   float x=9.4;
   float y=8.3;
   std::cout <<"Values of x and y are :"<<x<<","<<y<< std::endl;
   cout<<"Positive difference between two numbers is :"<<fdim(x,y);
    return 0;
}

Output:

Values of x and y are :9.4,8.3
Positive difference between two numbers is :1.1

In this example, value of x is greater than the value of y and fdim function finds the positive difference between x and y.

Example 2

Let's see a simple example when the value of 'x' is less than the value of 'y'.

#include <iostream>
#include<math.h>
using namespace std;
int main()
{
   double x=3.3;
   float y= 4.7;
   std::cout <<"Values of x and y are :"<<x<<","<<y<< std::endl;
   cout<<"Positive difference between two numbers is :"<<fdim(x,y);
    return 0;
}

Output:

Values of x and y are :3.3,4.7
Positive difference between two numbers is :0

In this example, value of x is less than the value of y so fdim function returns zero value.