Minimum Flips Required To Generate Continuous Substrings Of 0S And 1S In C++

In this article, we will discuss how to find the minimum flips required to generate continuous substrings of 0's and 1's in C++ .

Continuous character sequences is known as substrings of 0s and 1s. It can be created by selecting zero or more characters from the original string in any order, provided that no characters are missed.

Consider the string "1100" in this instance. There are the following substrings: "1", "0", "11", "10", "100", "110", and "1100". The empty string is a substring of all strings, and it may be generated by choosing precisely 0 characters from the original string.

Example 1:

Let us take a program to find a minimum number of flips needed to generate continuous substrings of 0's and 1's in C++.

#include<iostream>
#include<string>
using namespace std;
int minFlips(string s) {
    int flips = 0;
    char prev = s[0];
   
 for(int i=1;i<s.size();i++)
{
	If(s[i]!=prev)
	{
		flips++;
		prev=s[i];
	}    
}
    return flips;
}
int main() {
    string s;
    cout << "Enter a binary string: ";
    cin >> s;
    int minFlipsRequired = minFlips(s);
    cout << "Minimum flips required: " << minFlipsRequired << endl;
    return 0;
}

Output:

Explanation:

• ✅ Define Function minFlips: In the input binary string , this function counts the minimum number of flips needed to produce continuous substrings of 0's and 1s. Flips is initially set to 0, and prior is set to the string's first character. It begins at the second character, and continues through the string. The flips count is increased and the previous character is updated if the current character differs from the previous one. Ultimately, it yields the total number of flips.
• ✅ Main Function (primary): It requests a binary string input from the user. It reads the input string. It uses the input string to call the minFlips Results in the minimum number of flips needed to the console.
• ✅ In the input binary string , this function counts the minimum number of flips needed to produce continuous substrings of 0's and 1s.
• ✅ Flips is initially set to 0, and prior is set to the string's first character.
• ✅ It begins at the second character, and continues through the string.
• ✅ The flips count is increased and the previous character is updated if the current character differs from the previous one.
• ✅ Ultimately, it yields the total number of flips.
• ✅ It requests a binary string input from the user.
• ✅ It reads the input string.
• ✅ It uses the input string to call the minFlips
• ✅ Results in the minimum number of flips needed to the console.

Complexity Analysis:

Time Complexity:

The time complexity to find the minimum number of flips required is O(n).

Space Complexity:

The space complexity to find the minimum number of flips required is O(1).

Example 2:

Let us take a program to find a minimum number of flips needed to generate continuous substrings of 0's and 1's using Recursion in C++.

#include<iostream>
#include<string>
using namespace std;
int minFlips(string s, int index = 1, char prev = '\0', int flips = 0) {
    if (index >= s.size()) {
        return flips;
    }
    if (s[index] != prev) {
        return minFlips(s, index + 1, s[index], flips + 1);
    }
    return minFlips(s, index + 1, prev, flips);
}
int main() {
    string s;
    cout << "Enter a binary string: ";
    cin >> s;
    int minFlipsRequired = minFlips(s);
    cout << "Minimum flips required: " << minFlipsRequired << endl;
    return 0;
}

Output:

Explanation:

• ✅ Definition of Recursive Function minFlips: In the input binary string, this function determines the minimal number of flips needed to produce continuous substrings of 0s and 1s. Four parameters are required: s: The text entered. index: The index that is being processed right now. prev: The character that was encountered before. flips: Number of flips are there at the moment. It determines whether the index exceeds or equals the string's length. It returns the total number of flips if it is true. It recursively calls itself with an index incremented by 1, updating prev to s[index], and incrementing flips by 1 if the current character s[index] differs from the previous character prev. It calls itself recursively without increasing the count of flips if the current character is the same as the previous one. Ultimately, it gives back the outcome of the iterative calls.
• ✅ Main Function (primary): It requests a binary string input from the user. Reads the input string. Uses the input string to call the minFlips method. Results in the minimum number of flips needed to the console.
• ✅ In the input binary string, this function determines the minimal number of flips needed to produce continuous substrings of 0s and 1s.
• ✅ Four parameters are required:
• ✅ s: The text entered.
• ✅ index: The index that is being processed right now.
• ✅ prev: The character that was encountered before.
• ✅ flips: Number of flips are there at the moment.
• ✅ It determines whether the index exceeds or equals the string's length. It returns the total number of flips if it is true.
• ✅ It recursively calls itself with an index incremented by 1, updating prev to s[index], and incrementing flips by 1 if the current character s[index] differs from the previous character prev.
• ✅ It calls itself recursively without increasing the count of flips if the current character is the same as the previous one.
• ✅ Ultimately, it gives back the outcome of the iterative calls.
• ✅ It requests a binary string input from the user.
• ✅ Reads the input string.
• ✅ Uses the input string to call the minFlips method.
• ✅ Results in the minimum number of flips needed to the console.

Complexity Analysis:

Time Complexity:

The time complexity to find a minimum number of flips required is O(n).

Space Complexity:

The space complexity to find the minimum number of flips required is O(n).

Conclusion:

In conclusion, finding the minimum number of flips required to generate continuous substrings of 0s and 1s is a task whose solution depends on the constraints and specifications of the problem. The minimal amount of flips required to do this depends on the string and the characteristics of "nonstop" substrings. When it comes to solving difficulties, there are usually several different ways that can be used. For example, two alternative solutions for a similar problem are avaricious computations and dynamic programming .