C++ Program To Find If A Character Is A Vowel Or Consonant

In this article, we will discuss how to find a character is a vowel or constant in C++. If we want to check whether a letter is either a vowel or a consonant, we can use the program written below:

• ✅ Obtain User Input: Request that the user input a character.
• ✅ Store the Input: Capture the entered Character and store it in a variable (e.g., Character).
• ✅ Check if the Character is a Vowel: Check if the Character is equal to 'a', 'e', 'i', 'o' , or 'u' (all lowercase) using an if statement . If it matches any of these characters, consider it a vowel. You can check the uppercase versions of these letters ('A', 'E', 'I', 'O', 'U') separately if needed.
• ✅ Display the Result: If the Character is a vowel, print a message indicating it is a vowel . If the Character is not a vowel (i.e., it does not match any specified characters), assume it is a consonant and print a message indicating it's a consonant. If the input letter is one of the vowels in the given set, this function detects it as a vowel. It is considered a consonant otherwise.
• ✅ Check if the Character is equal to 'a', 'e', 'i', 'o' , or 'u' (all lowercase) using an if statement .
• ✅ If it matches any of these characters, consider it a vowel.
• ✅ You can check the uppercase versions of these letters ('A', 'E', 'I', 'O', 'U') separately if needed.
• ✅ If the Character is a vowel, print a message indicating it is a vowel .
• ✅ If the Character is not a vowel (i.e., it does not match any specified characters), assume it is a consonant and print a message indicating it's a consonant.
• ✅ If the input letter is one of the vowels in the given set, this function detects it as a vowel. It is considered a consonant otherwise.

In C++, there are several methods to determine if a given letter is a vowel or a consonant. The three common methods are switch-case statements, if-else statements , and a simpler method that makes use of arrays. Let us discuss each with an example:

Method 1: If-else statements

#include <iostream>
using namespace std;

int main() {
    char character;
    cout << "Enter a character: ";
    cin >> character;
    // Convert the Character to lowercase to handle both uppercase and lowercase letters
    character = tolower(character);

    if (character == 'a' || character == 'e' || character == 'i' || character == 'o' || character == 'u') {
        cout << character << " is a vowel." << endl;
    } else {
        cout << character << " is a consonant." << endl;
    }

    return 0;
}

Output:

Enter a character: a
a is a vowel.
Enter a character: B
b is a consonant.

Explanation:

In this code, we first convert the Character to lowercase to handle both uppercase & lowercase input. After that, using if-else expressions, we determine whether the Character is one of the vowels ( 'a', 'e', 'i', 'o', 'u' ).

Method 2: Using switch-case statements

#include <iostream>
using namespace std;

int main() {
    char character;
    cout << "Enter a character: ";
    cin >> character;

    // Convert the Character to lowercase to handle both uppercase and lowercase letters
    character = tolower(character);

    switch (character) {
        case 'a':
        case 'e':
        case 'i':
        case 'o':
        case 'u':
            cout << character << " is a vowel." << endl;
            break;
        default:
            cout << character << " is a consonant." << endl;
            break;
    }

    return 0;
}

Output:

Enter a character: e
e is a vowel.
Enter a character: X
x is a consonant.

Explanation:

In this code, we also convert the Character to lowercase and then use a switch-case statement to check if it matches any of the vowels.

Method 3: Using an array

#include <iostream>
#include <cstring>
using namespace std;

int main() {
    char character;
    cout << "Enter a character: ";
    cin >> character;

    // Convert the Character to lowercase to handle both uppercase and lowercase letters
    character = tolower(character);

    char vowels[] = {'a', 'e', 'i', 'o', 'u'};
    bool isVowel = false;

    for (int i = 0; i < strlen(vowels); i++) {
        if (character == vowels[i]) {
            isVowel = true;
            break;
        }
    }

    if (isVowel) {
        cout << character << " is a vowel." << endl;
    } else {
        cout << character << " is a consonant." << endl;
    }

    return 0;
}

Output:

Enter a character: i
i is a vowel.
Enter a character: Y
y is a consonant.

Explanation:

In this example, the vowels are stored in an array after this code initially makes the letter lowercase. We cycle over the array to check if the Character matches any of the vowels.

While all three methods reach the same result, they do so by identifying vowels and consonants in letters using various control structures. Choose the one that is the simplest to comprehend and best matches your specific application.

By using the Find Function:

Now, the find method , generally used with strings and holders, is not the immediate choice for this task. In similar cases, distinguishing whether a letter is a vowel or a consonant generally involves relative analysis.

To determine if a letter falls into the order of vowels or consonants using the discovery system , you'd search for it within a string of vowels. The following C++ program demonstrates this approach

Code:

#include <iostream>
#include <string>
using namespace std;

int main() {
    char character;
    string vowels = "aeiouAEIOU";

    cout << "Enter a character: ";
    cin >> character;

    // Check if the Character is found in the 'vowels' string
    if (vowels.find(character) != string::npos) {
        cout << character << " is a Vowel." << endl;
    } else {
        cout << character << " is a Consonant." << endl;
    }

    return 0;
}

Output for Various Inputs:

Input: 'a'
Output: "A is a Vowel."
Input: 'B'
Output: "B is a Consonant.