We can convert any decimal number (base-10 (0 to 9)) into binary number (base-2 (0 or 1)) by C++ program.
Decimal Number
Decimal number is a base 10 number because it ranges from 0 to 9, there are total 10 digits between 0 to 9. Any combination of digits is decimal number such as 223, 585, 192, 0, 7 etc.
Binary Number
Binary number is a base 2 number because it is either 0 or 1. Any combination of 0 and 1 is binary number such as 1001, 101, 11111, 101010 etc.
Let's see the some binary numbers for the decimal number.
| Decimal | Binary |
|---|---|
1 |
0 |
2 |
10 |
3 |
11 |
4 |
100 |
5 |
101 |
6 |
110 |
7 |
111 |
8 |
1000 |
9 |
1001 |
10 |
1010 |
Decimal to Binary Conversion Algorithm
Step 1: Divide the number by 2 through % (modulus operator) and store the remainder in array
Step 2: Divide the number by 2 through / (division operator)
Step 3: Repeat the step 2 until the number is greater than zero
Let's see the C++ example to convert decimal to binary.
Example
#include <iostream>
using namespace std;
int main()
{
int a[10], n, i;
cout<<"Enter the number to convert: ";
cin>>n;
for(i=0; n>0; i++)
{
a[i]=n%2;
n= n/2;
}
cout<<"Binary of the given number= ";
for(i=i-1 ;i>=0 ;i--)
{
cout<<a[i];
}
}
Output:
Enter the number to convert: 9
Binary of the given number= 1001