C Program To Print The Smallest Element In An Array

Consider the given array. Initially, the variable 'min' is assigned the value 25. During the first iteration, 'min' is compared with 11. As 11 is smaller than 25, 'min' is updated to 11. Moving to the second iteration, 11 is compared with 7. Since 7 is smaller than 11, 'min' is now set to 7. This process continues until all elements in the array have been checked. Finally, 'min' will store the smallest value found in the array.

ALGORITHM:

• ✅ STEP 1: START
• ✅ STEP 2: INITIALIZE arr = {25, 11, 7, 75, 56}
• ✅ STEP 3: length= sizeof(arr)/sizeof(arr[0])
• ✅ STEP 4: min = arr[0]
• ✅ STEP 5: SET i=0. REPEAT STEP 6 and STEP 7 UNTIL i<length
• ✅ STEP 6: if(arr[i]<min) min=arr[i]
• ✅ STEP 7: i=i+1.
• ✅ STEP 8: PRINT "Smallest element present in given array:" by assigning min
• ✅ STEP 9: RETURN 0.
• ✅ STEP 10: END.

PROGRAM:

Example
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#include <stdio.h>  

   

int main()  

{  

    //Initialize array   

    int arr[] = {25, 11, 7, 75, 56};    

      

    //Calculate length of array arr  

    int length = sizeof(arr)/sizeof(arr[0]);  

      

    //Initialize min with first element of array.  

    int min = arr[0];  

      

    //Loop through the array  

    for (int i = 0; i < length; i++) {   

        //Compare elements of array with min  

       if(arr[i] < min)  

           min = arr[i];  

    }    

    printf("Smallest element present in given array: %d\n", min);  

    return 0;  

}
Try it Yourself

Output:

Smallest element present in given array: 7