C Program To Print The Duplicate Elements Of An Array

The initial occurrence of a duplicated element within the array is identified at index 4, which corresponds to the element (2) that is duplicated from index 1. Therefore, the duplicate elements within the provided array are 2, 3, and 8.

ALGORITHM:

• ✅ STEP 1: START
• ✅ STEP 2: INITIALIZE arr= {1, 2, 3, 4, 2, 7, 8, 8, 3}.
• ✅ STEP 3: length = sizeof(arr)/sizeof(arr[0])
• ✅ STEP 4: PRINT "Duplicate elements in given array:"
• ✅ STEP 5: SET i=0. REPEAT STEP 6 to STEP 9 UNTIL i<length
• ✅ STEP 6: SET j=i+1. REPEAT STEP 7 and STEP 8 UNTIL i<length
• ✅ STEP 7: if(arr[i] == arr[j]) PRINT arr[j]
• ✅ STEP 8: j=j+1
• ✅ STEP 9: i+1.
• ✅ STEP 10: RETURN 0.
• ✅ STEP 11: END

PROGRAM:

#include <stdio.h>  

   

int main()  

{  

    //Initialize array   

    int arr[] = {1, 2, 3, 4, 2, 7, 8, 8, 3};   

      

    //Calculate length of array arr  

    int length = sizeof(arr)/sizeof(arr[0]);  

      

    printf("Duplicate elements in given array: \n");  

    //Searches for duplicate element  

    for(int i = 0; i < length; i++) {  

        for(int j = i + 1; j < length; j++) {  

            if(arr[i] == arr[j])  

                printf("%d\n", arr[j]);  

        }  

    }  

    return 0;  

}

Output:

Duplicate elements in given array:

2

3

8