C Program To Left Rotate The Elements Of An Array

If the value of n is 1, each element in the array will shift one position to the left. This means that the second element will become the first, the third element will move to the second position, and so forth. Simultaneously, the original first element will be appended to the end of the array.

ALGORITHM:

✅ STEP 1: START
✅ STEP 2: INITIALIZE arr ={1, 2, 3, 4, 5 }.
✅ STEP 3: length = sizeof(arr1)/sizeof(arr1[0])
✅ STEP 4: length = sizeof(arr)/sizeof(arr[0])
✅ STEP 5: SET n =3
✅ STEP 6: SET i=0. REPEAT STEP 7 to STEP 8 UNTIL i<length
✅ STEP 7: PRINT arr[i]
✅ STEP 8: i = i+1
✅ STEP 9: SET i= 0. REPEAT STEP 10 to STEP 16 UNTIL i<n
✅ STEP 10: DEFINE j, first.
✅ STEP 11: first = arr[0]
✅ STEP 12: SET j=0. REPEAT STEP 13 to STEP 14 UNTIL j<length-1.
✅ STEP 13: arr[j]= arr[j+1]
✅ STEP 14: j=j+1.
✅ STEP 15: arr[j]= first
✅ STEP 16: i=i+1.
✅ STEP 17: PRINT new line.
✅ STEP 18: PRINT "Array after left rotation"
✅ STEP 19: ENDSET i=0. REPEAT STEP 20 to STEP 21 UNTIL i<length
✅ STEP 20: PRINT arr[i]
✅ STEP 21: i=i+1.
✅ STEP 22: RETURN 0.
✅ STEP 23: END

PROGRAM:

Example


#include <stdio.h>  

   

int main()  

{  

    //Initialize array   

    int arr[] = {1, 2, 3, 4, 5};   

    //Calculate length of array arr  

    int length = sizeof(arr)/sizeof(arr[0]);  

    //n determine the number of times an array should be rotated  

    int n = 3;  

      

    //Displays original array  

    printf("Original array: \n");  

    for (int i = 0; i < length; i++) {   

        printf("%d ", arr[i]);   

    }    

      

    //Rotate the given array by n times toward left  

    for(int i = 0; i < n; i++){  

        int j, first;  

        //Stores the first element of the array  

        first = arr[0];  

      

        for(j = 0; j < length-1; j++){  

            //Shift element of array by one  

            arr[j] = arr[j+1];  

        }  

        //First element of array will be added to the end  

        arr[j] = first;  

    }  

      

    printf("\n");  

      

    //Displays resulting array after rotation  

    printf("Array after left rotation: \n");  

    for(int i = 0; i < length; i++){  

        printf("%d ", arr[i]);  

    }  

    return 0;  

}

Output:

Output


Original Array:

1   2   3   4   5

Array after left rotation:

4   5   1   2   3

ALGORITHM:

PROGRAM:

Input Required