- 45 bytes
- 9 bytes
- 27 bytes
Explanation:
The correct answer is option "a". The size of a 3x3 integer array in bytes must be determined by considering into account both the total number of elements in the array and the size of each element, since an integer (int) is equal to one byte. A 3x3 array has 3×3=9 elements altogether because of the 3 rows and 3 columns. The number of elements multiplied by the size of each element, which is expressed as an integer up to 4 bytes, provides the overall size of the array. Thus, the total size of the 3x3 integer array is 9×4=36 bytes.
- How is memory allocated for a two-dimensional array in C?
- Dynamically
- On the stack
- Continuously
- Non-contiguously
Explanation:
Memory for a 2D array in C can be dynamically allocated using functions such as malloc, calloc, or realloc from the heap. This enables developers to specify the array's size during program execution, a useful feature when the array's size may change during runtime or is not predetermined during compilation.
Memory is allocated in a contiguous block when a two-dimensional array is dynamically allocated. Double pointers, in which the firsLogic Practiceer leads to an array of pointers, each of which points to a row of the array, are commonly used to access the array. This ensures that the memory may be effectively accessed in row-major order and that it is contiguous.
- Which method is used for dynamically allocating a 2D array among the following?
- calloc
- realloc
- malloc
- All of the above
Explanation:
The correct answer is option "c". Using malloc, calloc, and realloc in C, dynamic memory allocation for a 2D array is achievable. Memory that has not been initialized is allocated by malloc, whereas calloc creates memory and sets its initial value to 0. When resizing 2D arrays, realloc can be useful because it adjusts the size of a memory block that has already been created. Based on the unique requirements of initialization and resizing, each function may be used to dynamically manage memory for 2D arrays.
- Can the size of a two-dimensional array be changed once it is declared?
- No, the size is fixed.
- Yes, using malloc.
- Yes, using realloc.
- Yes, by assigning a new array.
Explanation:
The correct answer is option "d". A two-dimensional array in C cannot have its dimensions dynamically altered during runtime after it is declared with a specific size. Because C uses statically allocated arrays, the size of an array is predetermined at compile time and remains fixed while the program executes. The process of resizing an array requires copying its elements from the old array to the new one and allocating a new array of the necessary size. This requires manual memory management and is not directly supported for statically defined arrays. Resizable arrays allocated on the heap are managed using dynamic memory allocation methods such as calloc, realloc, and malloc.
- What is the proper way to print all elements of a 2D array with nested loops using proper syntax?
- for(i=0; i<2; i++) { for(j=0; j<2; j++) { printf("%d ", arri); }}
- for(i=0; i<3; i++) { for(j=0; j<3; j++) { printf("%d ", arri); }}
- for(i=0; i<2; i++) { for(j=0; j<2; j++) { printf("%d ", arr[i]); }}
- for(i=0; i<=2; i++) { for(j=0; j<=2; j++) { printf("%d ", arri); }}
Explanation:
The correct answer is option "b".
The outer loop that iterates through the rows of the 2D array arr is represented by the for(i = 0; i < 3; i++) statement. This loop covers all three rows, as i varies from 0 to 2.
Inner Loop (Columns): The for loop with the condition for(j = 0; j < 3; j++) iterates over every column within row i during the current cycle. Here, j varies from 0 to 2, ensuring that all three columns of each row are processed.
This arrangement guarantees that the elements of the 2D array "arr" are printed in row-major sequence, showcasing them in the accurate order.